Question

8- Calcule: 1 00
(8x3 - 5x2 - 6+2x) - (-2x2 + 6x +8+2x) =​

Answer 1

$(8 {x}^{3} - {5x}^{2} - 6 + 2x) - ( - {2x}^{2} + {6x}^{3} + 8 + 2x)$

${8x}^{3} - {5x}^{2} - 6 + 2x + {2x}^{2} - {6x}^{3} - 8 - 2x$

${2x}^{3} - {3x}^{2} - 14$