Question

{[(8×4+3)÷7+(3+15÷5)×3]×2-(19-7)÷6}×2+12=

Answer 1

{[(8x4+3)/7+(3+15/5)x3]x2-(19-7)/6}x2+12=
{[35/7+6x3]x2-12/6}x2+12
{[5+18]x2-12/6}x2+12
{23x2-12/6}x2+12
{46-2}x2+12
44x2+12
88+12
100