Question

8^2÷(3^2−(1−2^3))+(−3)^1
Me ajudem pfvv​

Answer 1

$8^2:(3^2-(1-2^3))+(-3)^1$

$64:(9-(1-8))+(-3)$

$64:(9-(-7))-3$

$64:(9+7) - 3$

$64: 16 - 3$

$4-3$

$1$