Question

8-{(-1)⁷. (3²-√16)/(-1)⁰]}

Answer 1

$8 - \cfrac{(-1)^7 \cdot (3^2 - \sqrt{16})}{(-1)^0} \\\\= 8 - \cfrac{-1 \cdot (9 - 4)}{1} \\\\= 8 - (-1 \cdot 5) \\\\= 8 - (-5) \\\\= 8 + 5\\\\= 13$