Question

7- Utilizando a fórmula de Bhaskara, quais as raízes da equação: x² - 5x + 6 = 0?
6 pontos
a) x´ = -2 x´´ = -1
b) x´ = 1 x´´= 3
c) x´= 3 x´´ = 2
d) x´ = 4 x´´ = -1​

Answer 1

Resposta:

c) x´= 3 x´´ = 2

Explicação passo a passo:

$x^2-5x+6=0$

$x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:1\cdot \:6}}{2\cdot \:1}$

$x_{1,\:2}=\frac{-\left(-5\right)\pm \:1}{2\cdot \:1}$

$x_1=\frac{-\left(-5\right)+1}{2\cdot \:1},\:x_2=\frac{-\left(-5\right)-1}{2\cdot \:1}$

$x_1=\frac{-\left(-5\right)+1}{2\cdot \:1}=\frac{5+1}{2\cdot \:1}=\frac{6}{2\cdot \:1}=\frac{6}{2}=3$

$x_2=\frac{-\left(-5\right)-1}{2\cdot \:1}=\frac{5-1}{2\cdot \:1}=\frac{4}{2\cdot \:1}=\frac{4}{2}=2$

$x=3,\:x=2$