Question

7- Simplifique
as (n-2)! (n+2)!/
(n+3)! (n-1)!​

Answer 1

$\frac{(n-2)!(n+2)!}{(n+3)!(n-1)!} = \frac{(n-2)!(n+2)!}{(n+3)(n+2)!(n-1)(n-2)!} = \frac{1}{(n+3)(n-1)}$