Question

7) Encontre x' e x'' X²+5x+6=0 ​

Answer 1

$∆ = {b}^{2} - 4.a.c \\ ∆ =5 {}^{2} - 4 .1.6 \\ ∆ = 25 - 24 \\ ∆ = 1 \\ \\ x = \frac{ - b \pm \sqrt{∆} }{2.a} \\ \\ x = \frac{ - 5 \pm \sqrt{1} }{2.1} \\ \\ x = \frac{ - 5 \pm1}{2} \\ \\ x' = \frac{ - 5 + 1}{2} = \frac{ - 4}{2} = - 2 \\ \\ x" = \frac{ - 5 - 1}{2} = \frac{ - 6}{2} = - 3$