Question

7. Calcule o valor de x nas figuras:

Answer 1

a)$A) cos 45 = \sqrt 2/2 \\ \sqrt2/2= x/\sqrt3\\2x-\sqrt6\\x=\sqrt6/2\\\\\\B) sen60= \sqrt3/2\\\sqrt3/2=12/x\\x\sqrt3= 24\\x=24/\sqrt3\\(racionalizando)\\x=24\sqrt3/\sqrt{3} *\sqrt{3} \\x= 24\sqrt{3} / 3\\\\\\C) vou chamar de y o lado vertical do triângulosen 45 = \sqrt{2} /2\\y/3\sqrt{2} = \sqrt{2} /2\\2y=3\sqrt{2} * \sqrt{2} \\2y = 3 * 2\\y=6/2 \\y=3\\\\sen 30= 1/2\\ 3/x= 1/2\\x=6$