Question

7. A soma dos termos da PG (1/3, 1/9. 1/27, 1/81, ...) é:
a. 1/4
b. 1/2
c. 2/3
d. 1
e. 3/2

Answer 1

Resposta:

S = 1/2 (B)

Explicação passo-a-passo:

q = u2/u1 = (1/9)/(1/3) = 1/3

soma infinita

S = u1/(1 - q)

S = (1/3)/(1 - 1/3)

S = (1/3)/(2/3) = 1/2