Question

6y2(esse 2 seria 6y ao quadrado) + 9y = 0

Answer 1

6y2+9y=0
a=6 b=9 c=0
/\=b2-4.ac
/\=9(2)-4.6.0
/\=81-0
/\=81

x=-b+-{raiz de 81}/2.a
x=-9+-{raiz de 81}/2.6
x=-9+-9/12
x'=-9+9/12=0/12=0
x''=-9-9/12=-18/12=-6/4=-3/2

S=(0 , -3/2)