Question

6x² - x - 1 = 0
por favor me ajudem​

Answer 1

Explicação passo-a-passo:

$\sf 6x^2-x-1=0$

$\sf \Delta=(-1)^2-4\cdot6\cdot(-1)$

$\sf \Delta=1+24$

$\sf \Delta=25$

$\sf x=\dfrac{-(-1)\pm\sqrt{25}}{2\cdot6}=\dfrac{1\pm5}{12}$

$\sf x'=\dfrac{1+5}{12}~\Rightarrow~x'=\dfrac{6}{12}~\Rightarrow~\red{x'=\dfrac{1}{2}}$

$\sf x"=\dfrac{1-5}{12}~\Rightarrow~x"=\dfrac{-4}{12}~\Rightarrow~\red{x"=\dfrac{-1}{3}}$