Question

6x² + 3x = 1 + 2x alguém responde ai por favor ​

Answer 1

Resposta:

$\boxed{\boxed{\bf{\red{Olá}}}}$

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vamos lá

$6{x}^{2}+3x-1-2x=06x2+3x−1−2x=0$

$6{x}^{2}+3x-1-2x6x2+3x−1−2x$

$6{x}^{2}+x-16x2+x−1.$

$6{x}^{2}+x-1=06x2+x−1=0$

$6{x}^{2}+x-16x2+x−1$ 

$6{x}^{2}+3x-2x-1=06x2+3x−2x−1=0$

$3x(2x+1)-(2x+1)=03x(2x+1)−(2x+1)=0$

$(2x+1)(3x-1)=0(2x+1)(3x−1)=0$

$x=-\frac{1}{2},\frac{1}{3}$

$resposta ⠀☞ x=−21,31$

Answer 2

$6 x {}^{2} + 3x = 1 + 2x \\ 6x {}^{2} + 3x - 1 - 2x = 0 \\ 6x {}^{2} + x - 1 = 0 \\ 6x {}^{2} + 3x - 2x - 1 = 0 \\ 3x \times (2x + 1) - (2x + 1) = 0 \\ (2x + 1) \times (3x - 1) = 0 \\ 2x + 1 = 0 \\ 3x - 1 = 0 \\ x = - \frac{1}{2} \\ x = \frac{1}{3} \\ {\red{x1 = - \frac{1}{2} }} \\ {\red{x2 = \frac{1}{3} }}$