Question

√64 + 3√-64 + 6√64 = (obs: o 3 e o 6 são indices do radical ..

Answer 1

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$\sqrt{64} + \sqrt[3]{-64} + \sqrt[6]{64} = \\ \\ \sqrt{2^6} + \sqrt[3]{(-2)^6} + \sqrt[6]{2^6} = \\ \\ 2^3+(-2)^2+2= \\ \\ 8+(+4)+2= \\ \\ 8+4+2=14$