Question

62. Calcule.
a)
$( { x}^{2} + 3x - 4) \times (x - 2)$
b)
$( {c}^{3} + {4c}^{3} + c) \times (c - 1)$
20 pontos​

Answer 1

Resposta:

a)

x³-2x²+3x²-6x-4x+8

x³+x²-10x+8

b)

c⁴-c³+4c⁴-4c³+c²-c

5c⁴-5c³+c²-c

Answer 2

a)

(x^2 + 3x - 4)*(x - 2)

= x^3 - 2x^2 + + 3x^2 - 6x - 4x + 8

= x^3 + x^2 - 10x + 8

b)

(c^3 + 4c^3 + c)*(c - 1)

= (5c^3 + c)*(c - 1)

= 5c^4 - 5c^3 + c^2 - c