Question

6² : 3² + 4 x 10 – 12 =

Answer 1

$\boxed{\begin{array}{l}\sf 6^{2} \ \div \ 3^2 \ + \ 4 \ x \ 10 \ - \ 12 \ = \ ??\end{array}}$

primeiro vamos tirar os expoentes

do 6² e 3², que fica;

$\Box \ 6^2=6 \ . \ 6=36$

e

$\Box \ 3^2=3 \ . \ 3=9$

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$\Box \ \ 36\ \div \ 9+4 \ . \ 10-12=\\\/ \ \/ \ \ \ \ \ \ \ \ \ 4+40-12=\\\/ \ \ \ \ \ \ \ \ \ \ \ \ 44-12=\\\/ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =32$    

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resposta correta é;

R=32

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