Question

6 x ao quadrado + 5x + 1 = 0​

Answer 1

Resposta:

x' = - 4

      12  

x'' =  - 6

        12    

Explicação passo-a-passo:

6x² + 5x + 1 = 0​

a = 6, b = 5, c = 1

Δ = b² – 4ac

Δ = 5² – 4 · 6 · 1

Δ = 25 – 4 · 6

Δ = 25 – 24

Δ = 1

x =  - b ± √Δ

         2·a

x =  - 5 ± √1

         2·6

x =  - 5 ± 1

          12

x' = - 5 + 1 = - 4

          12      12

x'' =  - 5 - 1 = - 6

          12       12

Answer 2

$\Box \ \ \boxed{\begin{array}{l}\sf 6x^2+5x+1=0 \end{array}}\\\\\\\Box \ \ \boxed{\begin{array}{l}\sf a=6 \end{array}}\\\Box \ \ \boxed{\begin{array}{l}\sf b=5 \end{array}}\\\Box \ \ \boxed{\begin{array}{l}\sf c=1 \end{array}}$

$\Box \ \ \boxed{\begin{array}{l}\sf \Delta=5^2-4.6.1 \end{array}}\\\Box \ \ \boxed{\begin{array}{l}\sf \Delta=25-24 \end{array}}\\\Box \ \ \boxed{\begin{array}{l}\sf \Delta=1 \end{array}}$

$\Box \ \ \boxed{\begin{array}{l}\sf x=\dfrac{-b\pm\sqrt{\Delta}}{2.a} \end{array}}\\\Box \ \ \boxed{\begin{array}{l}\sf x=\dfrac{-5\pm1}{2.6} \end{array}}\\\Box \ \ \boxed{\begin{array}{l}\sf x=\frac{-5\pm1}{12} \end{array}}$

$\Box \ \ \boxed{\begin{array}{l}\sf x'=\frac{-5+1}{12} \end{array}}\boxed{\begin{array}{l}\sf x'=\frac{-4}{12} \end{array}}$

$\Box \ \ \boxed{\begin{array}{l}\sf x''=\frac{-5-1}{12} \end{array}}\boxed{\begin{array}{l}\sf x''=\frac{-6}{12} \end{array}}$

$S=\{\frac{-6}{12} \ , \ \frac{-4}{12} \}$

$\ \ \ \ \heartsuit\\|\underline{\overline{\mathcal{\boldsymbol{\LaTeX}}}}|$