Matemática, perguntado por marcelamaxcimovicz, 9 meses atrás

6) resolva as frações a seguir:
a) 1/2 + 3/2=
b) 4/3 + 5/3=
c) 5/6 + 2/6=
d) 1/2 + 1/3=
e) 1/2 + 1/4=
f) 1/3 + 1/4=
g) 3/4 - 2/3=
h) 2/5 - 1/3=
i) 6/4 - 1/7 + 1/2=
k) 1/2 + 3=​

Soluções para a tarefa

Respondido por Usuário anônimo
12

Explicação passo-a-passo:

a) \sf \dfrac{1}{2}+\dfrac{3}{2}=\dfrac{1+3}{2}=\dfrac{4}{2}=\red{2}

b) \sf \dfrac{4}{3}+\dfrac{5}{3}=\dfrac{4+5}{3}=\dfrac{9}{3}=\red{3}

c) \sf \dfrac{5}{6}+\dfrac{2}{6}=\dfrac{5+2}{6}=\red{\dfrac{7}{6}}

d) \sf \dfrac{1}{2}+\dfrac{1}{3}=\dfrac{3+2}{6}=\red{\dfrac{5}{6}}

e) \sf \dfrac{1}{2}+\dfrac{1}{4}=\dfrac{2+1}{4}=\red{\dfrac{3}{4}}

f) \sf \dfrac{1}{3}+\dfrac{1}{4}=\dfrac{4+3}{12}=\red{\dfrac{7}{12}}

g) \sf \dfrac{3}{4}-\dfrac{2}{3}=\dfrac{9-8}{12}=\red{\dfrac{1}{12}}

h) \sf \dfrac{2}{5}-\dfrac{1}{3}=\dfrac{6-5}{15}=\red{\dfrac{1}{15}}

i) \sf \dfrac{6}{4}-\dfrac{1}{7}+\dfrac{1}{2}=\dfrac{42-4+14}{28}=\dfrac{52}{28}=\red{\dfrac{13}{7}}

k) \sf \dfrac{1}{2}+3=\dfrac{1+6}{2}=\red{\dfrac{7}{2}}

Respondido por Kuriza
2

Resposta:

a) 1/2 + 3/2 = 4/2 = 2

b) 4/3 + 5/3 = 9/3 = 3

c) 5/6 + 2/6 = 7/6

d) 1/2 + 1/3 = 3/6 + 2/6 = 5/6

e) 1/2 + 1/4 = 2/4 + 1/4 = 3/4

f) 1/3 + 1/4 = 4/12 + 3/12 = 7/12

g) 3/4 - 2/3 = 9/12 - 8/12 = 1/12

h) 2/5 - 1/3 = 6/15 - 5/15 = 1/15

i) 6/4 - 1/7 + 1/2 = 42/28 - 4/28 + 14/28 = 52/28 = 26/14 = 13/7

k) 1/2 + 3 = 6/2 + 1/2 = 7/2

Explicação passo-a-passo:

Perguntas interessantes