Question

6. Resolva as expressões Numéricas abaixo:
a) (52 - 3.7) + (49 +3.2).2-23
b) (52 -32): 4 - (1 +2° +39)
c) (52 – 3.4). 2 + (32.23 + 3): 52 - 10:5
d) {25 - [12 + (7.3 - 4) – 7]}:5 + 32.2 + (82 - 52)
e) 24:8 + 17474 08000 + (23 - 25)
f) [(734 +39 +33 + 27 +12):8+ 289 – 10'): 2
g) (34:27)4: 19 + 103.53 + 4/81
h) 30+{162 - 56:[82:(13 - 9)2+24 + 291–200): 541
PRECISO DE CÁLCULOS URGENTE
35 PONTOS
​

Answer 1

a) (52 - 3.7) + (49 +3.2).2-23=

(52 - 21) + (49 +6).2-23=

31+ 55.2-23=

31+ 110-23=

141-23=

118

b) (52 -32): 4 - (1 +2° +39) =

20: 4 - (1 +1 +39) =

5-41=

-36

c) (52 – 3.4). 2 + (32.23 + 3): 52 - 10:5

(52 – 12). 2 + (736 + 3): 52 - 2 =

40. 2 + 739: 52 - 2 =

80 + 739: 52 - 2 =

739: 52+79=

(739+79*52)/52=

(739+4108 )/52=

4847 /52=93,21

d) {25 - [12 + (7.3 - 4) – 7]}:5 + 32.2 + (82 - 52) =

{25 - [12 + (21 - 4) – 7]}:5 + 64 + 30 =

{25 - [12 + 17 – 7]}:5+94  =

{25 - 22}:5+94  =

3/5+94=

(3+94*5)/5=

(3+470)/5=

473/5=94.6

e) 24:8 + 17474 08000 + (23 - 25) = ((FALTA ALGUMA COISA ENTRE 17474 E 08000?!))

3 + 17474 08000 -2) =

1+17474 08000=

17474 08001

f) [(734 +39 +33 + 27 +12):8+ 289 – 10): 2 =

[845:8+ 279): 2 =

[105,62+ 279): 2 =

384.62 :2=

192.31

g) (34:27)4: 19 + 103.53 + 4/81 =

(34:27)4: 19 + 5459 + 4/81 =

(34:27)4: 19 + 5459 + 4/81 =

$\frac{\frac{34}{27}*4 }{19} +5459+\frac{4}{81} =$

$\frac{34}{27}*4*\frac{1}{19}  +5459+\frac{4}{81}=$

$\frac{136}{513} +5459+\frac{4}{81}=$

$\frac{(136*81)+(5459*513*81)+(4*513)}{513*81} =$

$\frac{11016+226837827+2052}{41553} =$

$\frac{226850895}{41553} =$

5459,31

h) 30+{162 - 56:[82:(13 - 9)2+24 + 291–200]}: 541 =

30+{162 - 56:[82:(4)2+24 +91]}: 541 =

30+{162 - 56:[82:8+115 ]}: 541 =

30+{162 - 56:[10.25+115 ]}: 541 =

30+{162 - 56:125,25}: 541 =

30+{162 - 0.44710578842}: 541 =

30+{161.552894212 }: 541 =

30+0.29861902811=

≈30,29

Answer 2

Resposta:

) (52 - 3.7) + (49 +3.2).2-23=

(52 - 21) + (49 +6).2-23=

31+ 55.2-23=

31+ 110-23=

141-23=

118

b) (52 -32): 4 - (1 +2° +39) =

20: 4 - (1 +1 +39) =

5-41=

-36

c) (52 – 3.4). 2 + (32.23 + 3): 52 - 10:5

(52 – 12). 2 + (736 + 3): 52 - 2 =

40. 2 + 739: 52 - 2 =

80 + 739: 52 - 2 =

739: 52+79=

(739+79*52)/52=

(739+4108 )/52=

4847 /52=93,21

d) {25 - [12 + (7.3 - 4) – 7]}:5 + 32.2 + (82 - 52) =

{25 - [12 + (21 - 4) – 7]}:5 + 64 + 30 =

{25 - [12 + 17 – 7]}:5+94 =

{25 - 22}:5+94 =

3/5+94=

(3+94*5)/5=

(3+470)/5=

473/5=94.6

e) 24:8 + 17474 08000 + (23 - 25) = ((FALTA ALGUMA COISA ENTRE 17474 E 08000?!))

3 + 17474 08000 -2) =

1+17474 08000=

17474 08001

f) [(734 +39 +33 + 27 +12):8+ 289 – 10): 2 =

[845:8+ 279): 2 =

[105,62+ 279): 2 =

384.62 :2=

192.31

g) (34:27)4: 19 + 103.53 + 4/81 =

(34:27)4: 19 + 5459 + 4/81 =

(34:27)4: 19 + 5459 + 4/81 =

\frac{\frac{34}{27}*4 }{19} +5459+\frac{4}{81} =

19

27

34

∗4

+5459+

81

4

=

\frac{34}{27}*4*\frac{1}{19} +5459+\frac{4}{81}=

27

34

∗4∗

19

1

+5459+

81

4

=

\frac{136}{513} +5459+\frac{4}{81}=

513

136

+5459+

81

4

=

\frac{(136*81)+(5459*513*81)+(4*513)}{513*81} =

513∗81

(136∗81)+(5459∗513∗81)+(4∗513)

=

\frac{11016+226837827+2052}{41553} =

41553

11016+226837827+2052

=

\frac{226850895}{41553} =

41553

226850895

=

5459,31

h) 30+{162 - 56:[82:(13 - 9)2+24 + 291–200]}: 541 =

30+{162 - 56:[82:(4)2+24 +91]}: 541 =

30+{162 - 56:[82:8+115 ]}: 541 =

30+{162 - 56:[10.25+115 ]}: 541 =

30+{162 - 56:125,25}: 541 =

30+{162 - 0.44710578842}: 541 =

30+{161.552894212 }: 541 =

30+0.29861902811=

≈30,29