Question

6.Efetue as multiplicações, usando a propriedade do cancelamento quando possível:
a) 3/4*1/2=
b)9/7*3/4=
c)8/5**7/8=
d)17/7*4/17=
e)2/3*1/4*8/5=
f)14/5*2/7*49/6=
g)8/15*1/3*45/16=
h)3/7*4/9*14/3=
i)6/5*25/3*9/2=
j)16/15*7/14*5/8=
k)18/12*2/28*22/9=
l)147/18*9/49*4/21

Answer 1

Resposta:

Explicação passo-a-passo:

a) 3/4*1/2=3/8

b)9/7*3/4=27/28

c)8/5*7/8=>7/5

d)17/7*4/17=4/7

e)2/3*1/4*8/5=2/3*2/5=>4/15

f)14/5*2/7*49/6=4/5*49/6=>98/15

g)8/15*1/3*45/16=8/15*15/16=>1/2

h)3/7*4/9*14/3=4/21*14/3=>8/9

i)6/5*25/3*9/2=10*9/2=>5*9=45

j)16/15*7/14*5/8=56/105*5/8=>7/5

k)18/12*2/28*22/9=9/84*22/9=11/42

l)147/18*9/49*4/21=147/18*12/343=>294/1029