Question

6- Dada a Função y=x²-2x+1,calcule os zeros da função,as coordenadas do vértice,calcule x=0 e esboce seu Gráfico.

Answer 1

Raizes:

$x^2-2x+1=0\\\\\Delta=(-2)^2-4*1*1\\\\\Delta = 4 - 4\\\\\Delta = 0\\\\x=\frac{-b \pm \sqrt{\Delta}}{2a}\\ \\x_1=\frac{2+0}{2}=1\\ \\x_2=\frac{2-0}{2}=1$

As duas raizes são iguais a 1

Vertice:

$V = \left(-\frac{b}{2a}\;,\;-\frac{\Delta}{4a}\right)\\\\V=\left(-\frac{-2}{2*1}\;,\;-\frac{0}{4*1}\right)\\\\V=\left(-\frac{-2}{2}\;,\;-\frac{0}{4}\right)\\\\V=\left(1\;,\;0\right)$

Calcular x=0:

y = 0² - 2*0 + 1

y = 0 - 0 + 1

y = 1