Question

6. Dada a função f(x) = 3x2 – 4x – 3, calcule f( - 4) – f( - 3) + f( -1).

Answer 1

3(-4)²-4(-4)-3-[3(-3)²-4(-3)-3]+3(-1)²-4(-1)-3
3.16+16-3-[3.9+12-3]+3+4-3
48+13-[27+9]+4
35-36+4
-1+4
+3
espero q entenda. bom estudo

Answer 2

f(x) = 3x^2 – 4x – 3
calcule f( - 4) – f( - 3) + f( -1):

f(-4) = 3.(-4)^2 - 4.(-4) - 3
f(-4) = 3.16 + 16 - 3
f(-4) = 48 + 13
f(-4) = 61

f(-3)= 3.(-3)^2 - 4.(-3) - 3
f(-3) = 3.9 + 12 - 3
f(-3) = 27 + 9
f(-3) = 36

f(-1) = 3.(-1)^2 - 4.(-1) - 3
f(-1) = 3.1 + 4 - 3
f(-1) = 3 - 3 + 4
f(-1) = 4

= f( - 4) – f( - 3) + f( -1)
= 61 - 36 + 4
= 25 + 4
= 29

Resp.: 29