Question

5yau quadrado+ 2y=0​

Answer 1

5y² + 2y = 0

A= 5

B= 2

C= 0

∆= b² - 4ac

∆= 2² - 4 • 5 • 0

∆= 4 - 0

∆= 4

y= - b ± √∆ / 2a

y= - 2 ± √4 / 2 • 5

y= - 2 + 2 / 10

y'= - 2 + 2 / 10 = 0/10 = 0

y''= - 2 - 2/ 10 = - 4 / 10 = - 2/5

S= ( - 2/5 ; 0)

Answer 2

Resposta:

$S = \{ - \frac{2}{5} ; \: 0 \}$

Explicação passo-a-passo:

$5 {y}^{2} + 2y = 0 \\ y \cdot(5y + 2) = 0 \\ \\ \boxed{ \bf{y = 0} } \\ \\ 5y + 2 = 0 \\ 5y = 0 - 2 \\ 5y = - 2 \\ \boxed{ \bf{y = - \frac{2}{5} } }$