Question

5y²- 9y - 2 = 0
usando baskhara e delta

Answer 1

Resposta:

S= {2, -1/5}

Explicação passo-a-passo:

5y²-9y-2=0

a=5, b= -9 e c=-2

delta =b²-4ac

delta = (-9)²-4.5.-2

delta =81+40

delta =121

$\sqrt{121} = 11$

y'= [-(-9)+11]/2•5

y'=[9+11]/10

y'=20/10

y'=2

y"=[-(-9)-11]/2.5

y"=[9-11]/10

y"=-2/10 :(2/2)

y"= -1/5