Question

5y2-6y+1=0 resolva em bhaskara

Answer 1

5y^2-6y+1=0

Δ=(-6)^2-4.5.1

Δ=36-20

Δ=16

y'=6+√16/10

y'=6+4/10
y'=10/10=1

y"=6-4/10
y"=2/10
y"=1/5

Answer 2

$5y^2-6y+1=0\\\\a=5\ \ \ \ \ \ b=6\ \ \ \ \ \ \ c=1\\\\\Delta=b^2-4ac\\\Delta=(6)^2-4\cdot(5)\cdot(1)\\\Delta=36-20\\\Delta=16\\\\y= \dfrac{-b \frac{+}{-} \sqrt{\Delta}}{2a}\\\\\\y= \dfrac{-(-6) \frac{+}{-} \sqrt{16}}{2\cdot5}\\\\\\y= \dfrac{6 \frac{+}{-}4}{10}\\\\\\y'= \dfrac{6-4}{10}\\\\\\y'=\dfrac{1}{5}\\\\\\y"=\dfrac{6+4}{10}\\\\\\y"=1$

$\boxed{S=\bigg\{y\in\mathbb{R}/y=\dfrac{1}{5}\ ou\ y=1\bigg\}}$