Question

5xao quadrado -3x-2=0

Answer 1

$5 x^{2}$ - 3x -2 = 0
a= 5 b=-3 c=-2
Δ= $b^{2}$ -4ac
Δ= $(-3^){2}$ -4·5·(-2)
Δ= 9 + 40
Δ= 49

x= $\frac{-(-3) +- \sqrt{49}}{2*5}$
x= $\frac{3 +-7}{10}$

x'= $\frac{3+7}{10} = \frac{10}{10} = 1$
x''= $\frac{3-7}{10} = \frac{-4}{10} = \frac{-2}{5}$

Answer 2

Δ= (-3)² - 4·5·(-2) 
Δ= 9 + 40
Δ= 49

X= [-(-3) + √49]÷(2·5)
X= [3 + 7]÷10
X= 10÷10
X= 1

X= [-(-3) - √49]÷(2·5)
X= [3 - 7] ÷ 10
X= -4÷10
X= -2/5

x= 1 ou x= -2/5