Question

( 5x²-2x-7 ) + ( 4x²-x+3 ) =
( 5x²-2x-7 ) + ( 4x²-x+3 ) + ( x² + 3x ) =
( 5x²-2x-7 ) + ( 4x²-x+3 ) + ( x² + 3x ) + ( 4 ) =
( 5x²-2x-7 ) - ( 4x²-x+3 ) =
( 5x²-2x-7 ) - ( 4x²-x+3 ) - ( x² + 3x ) =
( 5x²-2x-7 ) - ( 4x²-x+3 ) - ( x² + 3x ) - ( 4 ) =

Answer 1

[tex](5 x^{2} - 2x-7) + (4 x^{2} -x+3) = 8 x^{4}-3x-4 

Answer 2

$( 5 x^{2} -2x-7 ) + ( 4 x^{2} -x+3 ) = 5 x^{2} -2x-7 +4 x^{2} -x+3= \\ \\ 5 x^{2} +4 x^{2} -2x-x-7+3=9 x^{2} -3x-4 \\ \\ \\ ( 5 x^{2} -2x-7 ) + ( 4 x^{2} -x+3 ) + ( x^{2} + 3x ) = \\ \\ 5 x^{2} -2x-7+4 x^{2} - x +3 +x^{2} + 3x= \\ \\ 5 x^{2} +4 x^{2} + x^{2} -2x-x+3x-7+3=10 x^{2} -3 x} +3 x} -4= \\ \\ 10 x^{2} -4$



$( 5 x^{2} -2x-7 ) + ( 4 x^{2} -x+3 ) + ( x^{2} + 3x ) + ( 4 ) = \\ \\ 5 x^{2} -2x-7 + 4 x^{2} -x+3 + x^{2} + 3x + 4= \\ \\ 5 x^{2} +4 x^{2} + x^{2} -2x-x+3x-7+3+4 \\ \\ 10 x^{2} -3x+3x-7+7=10 x^{2} \\ \\ \\ ( 5 x^{2} -2x-7 ) - ( 4 x^{2} -x+3 ) = 5 x^{2} -2x-7-4 x^{2} +x-3= \\ \\ 5 x^{2} -4 x^{2} -2x+x-7-3= x^{2} -x-10$

$( 5 x^{2} -2x-7 ) - ( 4 x^{2} -x+3 ) - ( x^{2} + 3x ) = \\ \\5 x^{2} -2x-7-4 x^{2} +x-3- x^{2} -3x= \\ \\ 5 x^{2} -4 x^{2} - x^{2} -2x+x-3x-7-3 =5 x^{2} -5 x^{2} -x-3x-10= \\ \\ -4x-10 \\ \\ \\ ( 5 x^{2} -2x-7 ) - ( 4 x^{2} -x+3 ) - ( x^{2} + 3x ) - ( 4 ) = \\ \\ 5 x^{2} -2x-7-4 x^{2} +x-3- x^{2} -3x-4= \\ \\5 x^{2} -4 x^{2} - x^{2} -2x-3x+x-3-7-4 = \\ \\ 5 x^{2} -5 x^{2} -5x+x-7-7=-4x-14$