Question

5x²-2x+1= 0

valor de delta

Answer 1

D = (-2)^2 - 4 * 5 * 1
D = 4 - 20
D = -16

Answer 2

Δ= b² -4.a.c
Δ=(-2)² -4.5.1
Δ=4-20
Δ=-16

Δ<0