Question

5x² 21x 4=0 formula de baskara

Answer 1

$5 x^{2} + 21x + 4 = 0$

Δ = $21^{2} - 4 * 5 * 4$

Δ = $21^{2} - 80$

Δ = 441 - 80

Δ = 361

$x_{1,2}$ = (-21) ± √361/2 * 5

$x_{1,2}$ = (-21) ± 19/2 * 5

$x_{1}$ = $\frac{(-21) + 19}{2 * 5}$

$x_{1}$ = $\frac{-2}{10}$

$x_{1}$ = $- \frac{1}{5}$

$x_{2}$ = -$\frac{-21-19}{2 * 5}$

$x_{2}$ = $\frac{-40}{10}$

$x_{2}$ = -4