Question

5x ao quadrado+4x-1=0

Answer 1

5x²+4x-1 = 0
1) encontre o valor do determinante
Δ = b²-4ac
Δ = 4²-4*5*(-1)
Δ = 16+20
Δ = 36

2) Use a fórmula de báskara
$x = \frac{-b\pm \sqrt{\Delta} }{2a} \\ \\ x= \frac{-4\pm6}{2*5} \\ \\ x'= \frac{2}{10}= \frac{1}{5} \\ \\ x" = \frac{-10}{10}=-1$