Question

-5t ao quadro 40t-80 na forma Bhaskara

Answer 1

-5t² + 40t - 80 = 0
/\ = 40² - 4.(-5).(-80)
/\ = 1600 - 1600
/\ = 0
x' = x" = -b/2a = -40/2.(-5) = -40/-10 = 4

Answer 2

- 5t² + 40t - 80 = 0   ( - 1 )
5t² - 40t + 80 = 0

a = 5
b = - 40
c = 80

Δ = b² - 4 . a . c
Δ = ( - 40)² - 4 . 5 . 80 
Δ = 1600 - 1600
Δ = 0

x = - b + - √Δ/2a
x = - ( - 40) + - √0/2.5
x = 40 + - 0/10

x' e x" = 4

S = { 4 }