Question

59- p.a (3,6,12...)
a)encontre o 10 termo
b)a ordem do termo 6144​

Answer 1

a) r=6-3=3

a10=a3+7r

a10=12+7.3

a10=12+21=33

b)

$n = \frac{an + a1}{r} + 1 \\ n = \frac{6144 + 3}{3} + 1 \\ n = 2049 + 1 = 2050$