Question

[(5²-2.3²)² + (25/5)³ - (39/3)²]² ÷ (8²-7.3²)^5

Answer 1

Olá.

$\dfrac{[(5^2-2\cdot3^2)^2+(25/5)^3 - (39/3)^2]^2}{(8^2-7\cdot3^2)^5}=\dfrac{[(25-2\cdot9)^2+(5)^3 - (13)^2]^2}{(64-7\cdot9)^5}= \\\\\\\dfrac{[(25-18)^2+125 - 169]^2}{(64-63)^5}=\dfrac{[(7)^2-44]^2}{(1)^5}= \dfrac{[49-44]^2}{1}=\dfrac{[5]^2}{1}=\\\\\\\dfrac{25}{1}=\boxed{\boxed{5}}$

A imagem é pra caso o LaTex falhe.
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Bons estudos.