Matemática, perguntado por uphfc75, 6 meses atrás

50- [( 6 x 8) : ( 12 + 4 )]=
a) 47
b) 46
c) 48



2) 38 +[ 7 x ( 6 + 3) – (17 x 3)]=
a) 49
b) 50
c) 51




3) 3 x [5 + (42 : 3 – 9 )] =
a) 31
b) 33
c) 30




4) 120 : [ 3 x 15 +( 2 x 7 + 1)=
a) 12
b) 2
c) 22



5) { 16 + [ 2 +(5 x 3) – (21 :7 +10)]}=
a) 22
b) 21
c) 20



6) (32 –10)x ( 20 –15)= *
a) 105
b) 110
c) 111

Soluções para a tarefa

Respondido por testede097
0

1) 50- [( 6 x 8) : ( 12 + 4 )]=

50-|48÷16|

50-|3|

50-3

47

2)38 +[ 7 x ( 6 + 3) – (17 x 3)]=

38+|7x × 9-51|

38+ 12

50

3)3 x [5 + (42 : 3 – 9 )] =

3 ×|5+(14-9)|

3 × |5+5|

3×|10|

3×10

30

4)120 : [ 3 x 15 +( 2 x 7 + 1)=

120÷60

2

5){ 16 + [ 2 +(5 x 3) – (21 :7 +10)]}=

16+| 2+15-(3+10)

16+|2+15-13

16+|4|

16 + 4

20

6) (32 –10)x ( 20 –15)=

22×5

110

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