{(50-3ao quadrado×5)ao quadrado÷[210-(4 elevado a 4-5ao quadrado-62÷2)]}=
Soluções para a tarefa
Respondido por
1
(50-9x5)²/[210-(256-25-31)]
(50-45)²/[210-200]
5²/10
25/10
2,5
(50-45)²/[210-200]
5²/10
25/10
2,5
Respondido por
0
Olá,
![\{(50-3^2*5)^2 \div [210-(4^4-5^2-62\div 2)]\}\\
\\
\{(50-9*5)^2 \div [210-(256-25-62\div 2)]\}\\
\\
\{(50-45)^2 \div [210-(256-25-31)]\}\\
\\
\{(5)^2 \div [210-(231-31)]\}\\
\\
\{25 \div [210-200]\}\\
\\
\{25 \div 10\}= \frac{25}{10} = \frac{5}{2} = 2,5\\](https://tex.z-dn.net/?f=%5C%7B%2850-3%5E2%2A5%29%5E2+%5Cdiv+%5B210-%284%5E4-5%5E2-62%5Cdiv+2%29%5D%5C%7D%5C%5C%0A%5C%5C%0A%5C%7B%2850-9%2A5%29%5E2+%5Cdiv+%5B210-%28256-25-62%5Cdiv+2%29%5D%5C%7D%5C%5C%0A%5C%5C%0A%5C%7B%2850-45%29%5E2+%5Cdiv+%5B210-%28256-25-31%29%5D%5C%7D%5C%5C%0A%5C%5C%0A%5C%7B%285%29%5E2+%5Cdiv+%5B210-%28231-31%29%5D%5C%7D%5C%5C%0A%5C%5C%0A%5C%7B25+%5Cdiv+%5B210-200%5D%5C%7D%5C%5C%0A%5C%5C%0A%5C%7B25+%5Cdiv+10%5C%7D%3D++%5Cfrac%7B25%7D%7B10%7D+%3D++%5Cfrac%7B5%7D%7B2%7D+%3D+2%2C5%5C%5C%0A "\{(50-3^2*5)^2 \div [210-(4^4-5^2-62\div 2)]\}\\
\\
\{(50-9*5)^2 \div [210-(256-25-62\div 2)]\}\\
\\
\{(50-45)^2 \div [210-(256-25-31)]\}\\
\\
\{(5)^2 \div [210-(231-31)]\}\\
\\
\{25 \div [210-200]\}\\
\\
\{25 \div 10\}= \frac{25}{10} = \frac{5}{2} = 2,5\\")
Espero ter ajudado, bons estudos!
Espero ter ajudado, bons estudos!
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