Question

5(y-2)+2(2-y)=-3-(2y+3)

Answer 1

5 ( y - 2) + 2 ( 2 - y) = -3 - ( 2y + 3)
5y - 10 + 4 - 2y = -3 - 2y - 3
3y -6 = -2y - 6
3y + 2y = -6  + 6
5y = 0
y = 0/5 = 0 ***

Answer 2

5(y-2)+ 2(2-y)= -3-(2y+3)
5y-10+4-2y= -3-2y-3
3y-6 = -6-2y
3y+2y= -6+6
5y=0
y= 0/5
y= 0