Question

5 x elevado a 2 - 3x - 2 = 0​

Answer 1

${5x}^{2} - 3x - 2 = 0 \\ delta = {( - 3)}^{2} - 4 \times 5 \times ( - 2) \\ delta = 9 + 40 = 49$

$x = \frac{ - ( - 3) + - \sqrt{49} }{2 \times 5} = > x = \frac{3 + - 7}{10}$

${x}^{i} = \frac{3 + 7}{10} = > {x}^{i} = \frac{10}{10} = > {x}^{i} = 1$

${x}^{ii} = \frac{3 - 7}{10} = > {x}^{ii} = \frac{ - 4}{10} \frac{ \div 2}{ \div 2} = > \\ {x}^{ii} = \frac{ - 2}{5}$

Espero ter ajudado