Question

5 Resolva, em R, as seguintes equações:
a) x2 – 313x + 6 = 0
b) (3x – 1)2 + (x - 2)2 = 25
c) 2 · (x + 3)2 – 5. (x + 3) + 2 = 0
d) x + 3 = 3
e) (x - 1) - (x + 3) = 5​

Answer 1

Resposta:

a) x2 - 313x + 6 =0

2× - 313x= -6

-311x= -6 .(-1)

311x= 6

x= 311/6

b) (3x - 1) 2 + (x - 2) 2= 25

6x - 2 + 2x - 4= 25

6x+2x=25+2+4

8x=31

x=31/8

c)2.(x+3)2-5.(x+3)+2=0

2x+6.2-5x-15+2=0

2x-5x=-12+15-2

3x=1

x=1/3

d) x+3=3

x=3-3

x=0

e)(x-1)-(x+3)=5

x-1-x-3=5

x-x=5+1+3

-x=9 .(-1)

x=-9