Question

5. Qual a massa de H2SO4 necessária para reagir com 20g de NaOH?
Dados:
O = 16
Na = 23
H = 1
S = 32
2NaOH + H2SO4 => Na2SO4 + 2H2O

Answer 1

$\mathsf{2NaOH+H_{2}SO_{4}\to~Na_{2}SO_{4}+2H_{2}O}$

cálculo das massas molares:

$\mathsf{m_{H_{2}SO_{4}}=2.1+32+4.16=2+32+64=98~g/mol}\\\mathsf{m_{NaOH}=23+16+1=40~g/mol}$

$\mathsf{98g\,de\,H_{2}SO_{4}\to~80g\,de\,NaOH}\\\mathsf{x\,g\,de\, H_{2}SO_{4}\to~20g\,de\,NaOH}$

$\mathsf{80x=1960}\\\mathsf{x=\dfrac{1960}{80}}\\\large\boxed{\boxed{\boxed{\boxed{\mathsf{x=24,5~g\,de\,H_{2}SO_{4}}}}}}$