Question

5) Determine a medida do lado oposto ao ângulo de 30° do triângulo a seguir:
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Answer 1

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$\tt \underline{C\acute{a}lculo~do~terceiro~\hat{a}ngulo:}\\\sf{180^\circ-30^\circ-15^\circ=135^\circ}\\\tt\underline{pela~lei~dos~senos:}\\\sf\dfrac{15\sqrt{2}}{sen(135^\circ)}=\dfrac{x}{sen(30^\circ)}\\\sf{x\cdot sen(135^\circ)=15\sqrt{2}\cdot sen(30^\circ)}\\\sf x\cdot\dfrac{\diagdown\!\!\!\!\!\sqrt{2}}{\diagdown\!\!\!2}=15\diagdown\!\!\!\!\!\sqrt{2}\cdot\dfrac{1}{\diagdown\!\!\!2}\\\huge\boxed{\boxed{\boxed{\boxed{\sf x=15}}}}$