Question

5) Calcule a expressões e sempre que possivel simplifique o.




ME AJUDEM PIR FAVOR SE ​

Answer 1

Resposta:

A )

$\frac{2}{3} \div (-\frac{4}{7}) = \frac{2}{3\;.\;\frac{(-4)}{7} } = -\frac{2\;.\;7}{3\;.\;4} = -\frac{7}{6}$

B )

$-\frac{1}{2} \div (-\frac{4}{7}) = \frac{1}{2\;.\;\frac{4}{7} } = \frac{7}{2\;.\;4} = \frac{7}{8}$

C )

$\frac{7}{5} \div (-\frac{3}{8}) = -\frac{7}{5\;.\;\frac{3}{8} } = -\frac{7\;.\;8}{5\;.\;3} = -\frac{56}{15}$

D )

$-\frac{3}{5} \div (-\frac{1}{3}) = -\frac{3}{5\;.\;\frac{1}{3} } = -\frac{3\;.\;3}{5} = -\frac{9}{5}$

E )

$\frac{1}{3} \div \frac{3}{5} = \frac{1}{3\;.\;\frac{3}{5} } = \frac{5}{3\;.\;3} = \frac{5}{9}$

F )

$\frac{1}{7} \div (-\frac{3}{5}) = -\frac{1}{7\;.\;\frac{3}{5} } = -\frac{5}{7\;.\;3} = -\frac{5}{21}$

G )

$-\frac{8}{3} \div \frac{3}{6} = -\frac{8}{3\;.\;\frac{3}{6} } = -\frac{8\;.\;6}{3\;.\;3} = -\frac{48}{9} = -\frac{16}{3}$