Question

5 = -4t²- 2t me ajudem por favor

Answer 1

$5=-4t^2-2t\\-4t^2-2t=5\\-4t^2-2t-5=5-5\\-4t^2-2t-5=0\\t_{1,\:2}=\frac{-\left(-2\right)\pm \sqrt{\left(-2\right)^2-4\left(-4\right)\left(-5\right)}}{2\left(-4\right)}\\t_{1,\:2}=\frac{-\left(-2\right)\pm \:2\sqrt{19}i}{2\left(-4\right)}\\t_1=\frac{-\left(-2\right)+2\sqrt{19}i}{2\left(-4\right)}t=-\frac{1}{4}-i\frac{\sqrt{19}}{4},\:t_2=\frac{-\left(-2\right)-2\sqrt{19}i}{2\left(-4\right)}t=-\frac{1}{4}+i\frac{\sqrt{19}}{4}\\S[-\frac{1}{4}-i\frac{\sqrt{19}}{4},-\frac{1}{4}+i\frac{\sqrt{19}}{4}]$