Question

(√5+3√2+√98)×(√20+2√32)

Answer 1

(RAiz 5 = 2,23606) + ( 3raiz 2 =  4,2426 )+ (raiz 98 = 9,8994) = 16,378
(raiz 20 = 4,472) + (2raiz32 = 11,313)   =15,785

16,378 x 15,785   = 258,540

Espero ter ajudado! Boa sorte! 

Answer 2

$( \sqrt{3} +3 \sqrt{2} + \sqrt{2. 7^{2} } ).(2 \sqrt{3} +2 \sqrt{ 2^{4}.2 } )=$

$( \sqrt{3} +3 \sqrt{2} +7 \sqrt{2} ).(2 \sqrt{3} +8 \sqrt{2} )=$

$( \sqrt{3} +10 \sqrt{2} ).(2 \sqrt{3}+8 \sqrt{2} )=$

$2 \sqrt{ 3^{2} } +8 \sqrt{3} . \sqrt{2} +20 \sqrt{2}. \sqrt{3} +80 \sqrt{ 2^{2} }$

$6+8 \sqrt{6} +20 \sqrt{6} +160=$

$28 \sqrt{6} +166$