Question

5          3
..... - ....... = 0
t-1     1+t

Answer 1

    5          3
-------  - -------  =    0    
 t - 1     1 + t
m.m.c = (1+ t) (t - 1 )

5(1 + t)/ (1+t)(t - 1)     -     3 ( t - 1 ) / (t - 1 ) (1 + t)  = 0 eliminar o denominador
5 (1 + t)  -  3( t - 1 ) = 0
5 + 5 t = -3 t + 3 = 0
2 t + 8 = 0
2 t = -8
t = -8/2
t = - 4