Question

(4x4 – 4x³ + 12x) : 4x³



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Answer 1

Resposta:

15+12x

Explicação passo-a-passo:

$(4.4 - 4x^3 +12x):4x^3\\4x^3 : 4x^3 = 1\\logo\\(4.4 - 1 +12x)=15+12x$

Answer 2

$\huge{\boxed{\boxed{ \tt \:\frac{4x^4-4x^3+12x}{4x^3}=\frac{x^3-x^2+3}{x^2}\: }}}\\\\\huge{\boxed{\boxed{ \tt \: \frac{4x\left(x^3-x^2+3\right)}{4x^3}\: }}}\\\\\huge{\boxed{\boxed{ \tt \: \mathrm{Eliminar\:o\:fator\:comum:}\:4\: }}}\\\\\huge{\boxed{\boxed{ \tt \:\mathrm{Aplicar\:as\:propriedades\:dos\:expoentes}: \: }}}\\\\\huge{\boxed{\boxed{ \tt \:a^{b+c}=a^b\cdot \:a^c \: }}}\\\\\huge{\boxed{\boxed{ \tt \: x^3=xx^2\: }}}$

$\huge{\boxed{\boxed{ \tt \:\frac{x\left(x^3-x^2+3\right)}{xx^2} \: }}}\\\\\huge{\boxed{\boxed{ \tt \:\mathrm{Eliminar\:o\:fator\:comum:}\:x \: }}}\\\\\huge{\boxed{\boxed{ \tt \: \frac{x^3-x^2+3}{x^2}<<<\: }}}$