Question

4x³+8-3x² dividido por x+1 AJUDA PFVR

Answer 1

(4x³+8-3x^2) ÷ (x+1)    =    (4x³-3x^2+8) ÷ (x+1)

Utilizando o método da chave, temos

$\left\begin{array}{cccl}&~4x^3-3x^2+8&~~&\underline{|~x+1~~~~~~~~~~~~~~~~}\\-&\underline{~~~~4x^3+4x^2~~~~}&&~\,4x^2\\&-7x^2+8&&\end{array}\right\\\\\\\\\left\begin{array}{cccl}&~-7x^2+8&~~&\underline{|~x+1~~~~~~~~~~~~~~~~}\\-&\underline{~~~~-7x^2-7x~~~~}&&~\,4x^2-7x\\&7x+8&&\end{array}\right$

$\left\begin{array}{cccl}&~7x+8&~~&\underline{|~x+1~~~~~~~~~~~~~~~~}\\-&\underline{~~~~7x+7~~~~}&&~\,4x^2-7x+7\\&1&&\end{array}\right$

Portanto temos que o quociente vale 4x²-7x+7 e o resto da divisão vale 1.

Answer 2

Resposta:

4x³+8-3x² dividido por x+1

Utilizando Ruffini

x+1=0 ==>x=-1

     |    4     |   -3      |      0    |      8

-1   |    4     |   -7      |      7    |       1 ==> Resto

        4x²     -7x      +    7   ==>Q(x)

Q(x)=4x²-7x+7

R(x)=1