Question

(4x³-6x²+3x)-(7x³-6x²+8x)

Answer 1

    $(4x^3-6x^2+3x)-(7x^3-6x^2+8x)=$

$=4x^3-6x^2+3x-7x^3+6x^2-8x=$

$=4x^3-7x^3-6x^2+6x^2-8x+3x=$

$=-3x^3+0-5x=$

$=-3x^3-5x$