Question

4x²=5(4x-5) me ajudem pfv

Answer 1

4x^2=5.(4x-5)
4x^2=20x-25
4x^2-20x+25=0
delta=b^2-4ac
delta=(-20)^2-4.4.25
delta=400-400
delta=0
x=-b-/+ raiz de delta/2a
x=-(-20)-0/2.4
x=20-0/8
x=20/8 (÷4)
x=5/2