Question

( 4x2 + 3xy + y2 ) + ( -3x2 + 4xy ) + ( x2 - y2 )

Answer 1

Resposta:

$(4x^2+3xy+y^2)+(-3x^2+4xy)+(x^2-y^2)=\\ \\ 4x^2+3xy+y^2-3x^2+4xy+x^2-y^2=\\ \\ 4x^2+x^2-3x^2+3xy+4xy+\not y^2-\not y^2=\\ \\ \boxed{2x^2+7xy}$