Question

4x² -20x=0 formula de bascara

Answer 1

Resposta:

$4x^{2} -20x=0\\ \\ coeficientes:a=4,~b=-20,~c=0\\ \\ Bhaskara:\\ \\ x=\frac{-b+-\sqrt{b^{2}-4.a.c} }{2.a} \\ \\ x=\frac{-(-20)+-\sqrt{(-20)^{2}-4.4.0 } }{2.4} \\ \\ x=\frac{20+-\sqrt{400-0} }{8} \\ \\ x=\frac{20+-20}{8}\\ \\ x'=\frac{20-20}{8} =\frac{0}{8} =0\\ \\ x''=\frac{20+20}{8} =\frac{40}{8} =5\\ \\ S\left \{ {{0,~5} {}} \}$

$Formula~reduzida~(termo~comum~em~evidencia)\\ \\ 4x^{2} -20x=0\\ \\ x(4x-20)=0\\ \\ x_{1} =0\\ \\4x-20=0\\ \\ 4x=20\\ \\ x=\frac{20}{4} \\ \\ x_{2} =5\\ \\ S\left \{ {{0,~5} {}} \}$