Question

4x² -12x + 9 = 0 resolva ​

Answer 1

Resposta:

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~4x^{2}-12x+9=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=4{;}~b=-12~e~c=9\\\\\Delta=(b)^{2}-4(a)(c)=(-12)^{2}-4(4)(9)=144-(144)=0\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-12)-\sqrt{0}}{2(4)}=\frac{12-0}{8}=\frac{12\div4}{8\div4}=\frac{3}{2}\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-12)+\sqrt{0}}{2(4)}=\frac{12+0}{8}=\frac{12\div4}{8\div4}=\frac{3}{2}\\\\S=\{\frac{3}{2},~\frac{3}{2}\}$